The sequence above is geometric progression.
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909

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3 years ago

A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul

jeka94

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e. there are 2 choices to answer each question.

Now, the number of ways to answer Part A : $2^7=128$ (1)