Solve by Factoring x^(2/3)-7x^(1/3)+10=0
x
2
3
−
7
x
1
3
+
10
=
0
x
2
3
-
7
x
1
3
+
10
=
0
Rewrite
x
2
3
x
2
3
as
(
x
1
3
)
2
(
x
1
3
)
2
.
(
x
1
3
)
2
−
7
x
1
3
+
10
=
0
(
x
1
3
)
2
-
7
x
1
3
+
10
=
0
Let
u
=
x
1
3
u
=
x
1
3
. Substitute
u
u
for all occurrences of
x
1
3
x
1
3
.
u
2
−
7
u
+
10
=
0
Answer:
$203.02
Step-by-step explanation:
Since the bank in question compounds interest continuously, the following equation should be used to determine the final balance (B) in April's account:

Where "e" is a mathematical constant approximated as 2.7183, "i" is the interest rate (1.5%) and "t" is the investment time in years (1):


April's balance would be $203.02 after one year.
c
All the information you need is in the quadratic trinomial ... Read from right to left:
Find factors of 49 which ADD (+) to give 14.
These will be 7
and
7 because:
7
×
7
=
49
and
7
+
7
=
14
The + sign shows that the signs in the brackets will be the SAME, the minus (-) shows that they will be negative:
(
x
−
7
)
(
x
−
7
)
=
(
x
−
7
)
2
Answer:
-30
Step-by-step explanation:
In g(8) the 8 = n. So, substitute 8 in for n in the expression -4n + 2
g(8) = -4(8) + 2 = -32 + 2 = -30
<h2>
The required "option D) 3.09" is correct.</h2>
Step-by-step explanation:
Given,
A portfolio has a E[r] = 12 %, and
A standard deviation (
) = 18 %
We know that,
Specify utility by U = E(r) – 0.5A
U = 0.12– 0.5(A) × 
= 0.12 - 0.5 × A × 0.0162
In order for the risky portfolio to be preferred to bills,
The following condition must have:
0.12 – 0.0162A > 0.07
⇒ A <
= 3.09
A must be less than 3.09 for the risky portfolio to be preferred to bills.
Thus, the required "option D) 3.09" is correct.