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3 years ago

A rectangle has four right angles. What other shape has four right angles?

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer:

Square

Explanation:

A square is the only other shape with 4 right angles

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Match each set of numbers with their least common multiple

myrzilka [38]

27, 12, and 36 = 108

22 and 4 = 44

14 and 12 = 84

25 and 8 =200

9, 8, and 7 = 504

32, 24, and 18 = 288

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3 years ago

The city of Hamden received money for improvements of the town’s park. The park committee polled a random sample of 75 residents

Effectus [21]

<span>About a third of the residents prefer a park improvement of more trees.</span>

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3 years ago

Read 2 more answers

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago

34 is what percent of 80? (Round to the nearest whole number)

Marizza181 [45]

Answer:

42.5

34:80*100 =

(34*100):80 =

3400:80 = 42.5

8 0

3 years ago

Find the distance (-4,5) and (7,18)

seropon [69]

Answer:

$\sqrt{290}\ units$

Step-by-step explanation:

The distance between points $(x_1,y_1)$ and $(x_2,y_2)$ is

$\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Hence, the distance between points $(-4,5)$ and $(7,18)$ is

$\sqrt{(-4-7)^2+(5-18)^2}\\ \\=\sqrt{(-11)^2+(-13)^2}\\ \\=\sqrt{121+169}\\ \\=\sqrt{290}\ units$

3 0

3 years ago