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3 years ago

This transformation will produce similar, but not congruent, figures.

1 answer:

6 0

Two triangles are said to be congruent when the have the same sides and the same angles. When a figure is dilated by a value, the size of that figure changes.
Therefore, when Triangle MNO is reflected across the y-axis and then dilated by a scale factor of 1.8 to form triangle MꞌꞌNꞌꞌOꞌꞌ, the two triangles are similar but not congruent.

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What is the following product? Assume y >/= 0

spin [16.1K]

$\sqrt{y^3} * \sqrt{y^3}= \sqrt{y^3*y^3}= \sqrt{y^6}=y^{ \frac{6}{2} } =y^3$

7 0

3 years ago

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Fred and Victoria provide the following proofs for vertical angles to be equal:

mart [117]

Answer should be <span>Both Fred's and Victoria's proofs are correct.</span>

8 0

3 years ago

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The questions is on the picture

allochka39001 [22]

Answer:

EASY:

Step-by-step explanation:

-7 > -12

2 > -2

-5 < -3

|-9| is maybe 9.

|13| is 13.

|-5| is maybe 5.

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2 years ago

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Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

2 years ago

Somebody help me with this please!!

Slav-nsk [51]

Notice the following pattern:

2 - 0 = 2

6 - 2 = 4

12 - 6 = 6

20 - 12 = 8

It's reasonable to assume that consecutive terms in the sequence differ by increasing multiples of 2, so that for the next number (call it x) we expect to see

x - 20 = 10 ==> x = 30

and for the number after that (call it y) we would see

y - x = y - 30 = 12 ==> y = 42

4 0

3 years ago