Help me with this please

Mathematics

1 answer:

netineya [11]3 years ago

6 0

You add 21 and 18 to get 39 then divide it by the lowest number that can go into it so it
would be 3 so 3 goes into 39 13 times there for it would be 13

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X^2+ 6x - 4 = 3x + 6

jolli1 [7]

Answer:

x=2

x=-5

Step-by-step explanation:

You need to get everything on one side to have a quadratic equation:

x^2+6x-4 -(3x+6) = x^2+3x-10

All factors of 10 are 1*10 and 2*5.

5-2 = 3 and 5*-2 = -10

Factoring x^2+3x-10 gives us (x-2)(x+5)

x=2

x=-5

4 0

3 years ago

Read 2 more answers

Use Cramer’s Rule to solve system of equation.

alisha [4.7K]

$\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108$

$W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6$