99 POINTS! HELP

2 answers:

8 0

∠ABC ≅ ∠DEF - given
∠GHI ≅ ∠DEF - given
∠DEF ≅ ∠GHI - symmetric property
∠ABC ≅ ∠GHI - transitive property
m∠ABC = m∠GHI - definition of ≅ angles

Vikki [24]3 years ago

3 0

Answer:

∠ABC ≅ ∠DEF- given

∠GHI ≅ ∠DEF- given

∠DEF ≅ ∠GHI- symmetric property

∠ABC ≅ ∠GHI- transitive property

m∠ABC = m∠GHI- definition of ≅ angles

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BRAINLIEST AWARD NO.2

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Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

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$a_n=a_{n-1}*3+6$

we also know that the first term is 4

Then in this case, the first five terms are:

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$a_n=a_{n-1}*3+6\\a_n-6=a_{n-1}*3\\\frac{a_n-6}{3} = a_{n-1}\\a_{n-1}=\frac{a_n}{3} -2$

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

$a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49$

therefore, the starting first term should be at least about 121 to give a fifth term larger than 10,000

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