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monitta
2 years ago
8

A jar contains 99 large red​ marbles, 66 small red​ marbles, 88 large blue​ marbles, and 55 small blue marbles. if a marble is c

hosen at​ random, which of the conditional probabilities is​ larger, ​p(blueblue​|large large​) or ​p(larger large​|blueblue​)
Mathematics
1 answer:
aliina [53]2 years ago
3 0
I think it would be the first one
You might be interested in
1. A school store sells pencils and erasers before school opens each day. On Monday, 13 pencils and
JulsSmile [24]

Answer:

price of pencil is 0.74 and eraser is 0.72$

Step-by-step explanation:

Let, "p" represent pencils

and "e" represents erasers.

hence, according to question

13p+10e=16.75 ________(1)

and 25p+2e=19.85________(2)

Multiplying equation (2) by 5,

hence, 125p+10e=99.25________(3)

Substracting equation (3) and (1)

125p+10e-(13p+10e)=99.25-16.75

hence, 112p=82.5

p=0.74

substituting the value in equation (1),

13(0.74)+10e=16.75

9.57+10e=16.75

on solving,

e=0.72

hence, price of one pencil is 0.75$, and price of one eraser is $0.72

4 0
3 years ago
Find all the roots of the equation x4 - 2x3 + 14x2 - 18x + 45 = 0 given that 1 + 2i is one of its roots.
patriot [66]
Asked and answered elsewhere.
brainly.com/question/10192511


Knowing that 1+2i is a root, you also know that 1-2i is a root, so one quadratic factor is
   (x -1)² -(2i)² = x^2 -2x +5

Long division of the given polynomial by this quadratic gives a quotient of 
  x² +9
which has roots ±3i.

Then all the roots are {-3i, 3i, 1-2i, 1+2i}.
7 0
3 years ago
Which of the following rational functions is graphed below?
lukranit [14]

<h2>1 \: root \: solving\: f(x) = 0 \\ x = 0 \\  \\ vertical \: asymptote \: at \\ x = 1 \:  \:  \: and \:  \:  \: x =  - 4 \\  \\ f(x) =  \frac{x}{(x  + 4)(x - 1)}</h2><h2>Option C</h2>

i just got a notification

4 0
1 year ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
A ship sails 20km due North and then 35km due East .How far east is it from its starting point?
atroni [7]

Use the Pythagoras' Theorem:

A^2 + B^2 = C^2

20^2 + 35^2 = C^2

400+ 1225=1625=C^2

square root of 1625= C = 40.31 km

6 0
3 years ago
Read 2 more answers
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