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3 years ago

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You offer senior citizens a 20% discount on their tune-ups at your gas station. Assuming that an average of 50 senior citizens g

et a tune-up monthly at your station and that the average price of a tune-up before discount is $49.95, how much total discount do you give on an average monthly basis? $499.50 $1,248.75 $2,497.50 $12,487.50

1 answer:

Natali5045456 [20]3 years ago

6 0

499.50 is the total amount of discounts given to senior citizens

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In which of the number lines does the plotted point represent a number greater than -1 1/2? Check all that apply.

Nikitich [7]

Hi!

The first number line is equals to $-1\frac{1}{2}$

The second number line is equals to $\frac{-1}{2}$

The third number line is equals to $-2\frac{1}{2}$

The fourth number line is equals to 2

The fifth number line is equals to 0

The sixth number line is $-2\frac{3}{4}$

The answer is; second, fourth and fifth number lines.

<em></em>

<em>I hope, I could help.</em>

<em>Wish Good Lessons! ^-^</em>

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3 years ago

Read 2 more answers

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

<h3><u>1. x² - 36</u></h3>

$\sf \: x ^ { 2 } - 36$

Rewrite $\sf\:x^{2}-36 as x^{2}-6^{2}$ . The difference of squares can be factored using the rule: $\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

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<h3><u>2. 49 - x²</u></h3>

$\sf \: 49 - x ^ { 2 }$

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

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<h3><u>3. 81 - c²</u></h3>

$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

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<h3><u>4</u><u>.</u><u> </u><u>m²</u><u>n</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u></h3>

$\sf \: m ^ { 2 } n ^ { 2 } - 1$

Rewrite m²n² - 1 as $\sf\left(mn\right)^{2}-1^{2}$ . The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(mn-1\right)\left(mn+1\right) }}$

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3 years ago

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Which of the following is equal to the expression (8x)^-2/3 (27x)¯1/3

LiRa [457]

The equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

<h3>How to evaluate the expression?</h3>

The expression is given as:

(8x)^-2/3 * (27x)^-1/3

Evaluate the exponent 8^-2/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * (27x)^-1/3

Evaluate the exponent (27x)^-1/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * 1/3(x)^-1/3

Multiply 1/4 and 1/3

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^-2/3 * (x)^-1/3

Evaluate the exponent

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-2/3 -1/3)

This gives

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-1)

So, we have

(8x)^-2/3 * (27x)^-1/3 = 1/12x

Hence, the equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

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1 year ago

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LekaFEV [45]

Answer:

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3 years ago

In mrs.smiths class every time you turn in 10 assignments you earn 1 homework pass.Write 3 equivalent ratios if turned in assign

frutty [35]

Answer:

Step-by-step explanation:

For every 10 assignments you get 1 homework pass. So you would multiply them by two and up more.

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3 years ago