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NeTakaya
3 years ago
7

Which equation can be used to find the volume of a sphere that has a radius of 9 miles?

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
V=(4/3)pir^3

r=9
V=(4/3)pi9^3
V=12pi243
V=972pi

aprox pi=3.14
3052.08 mi^3
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Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
When ms Thelma turned one her oven ,the temperateure inside was 70 degress. The temputure began to rised at a rate of 40 per min
Ronch [10]

Answer:

7 minutes

Step-by-step explanation:

First, subtract 70 from 350.

350-70=280

Now, divide 280 by 40

280/40=7

It took Ms. Thelmas oven to heat up from 70 degrees to 350 degrees in 7 minutes.

3 0
3 years ago
What is the degree of the following polynomial?<br> 15x + 9x2 - 6x3 + 1
andrey2020 [161]

Answer:

3

Step-by-step explanation:

the one have largest power

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3 years ago
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Step2247 [10]

Answer:

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<h3>Square frustum</h3>

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