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WITCHER [35]
3 years ago
7

Find the equation of the line that passes through the points (-4, 2) and (1, -8). Use the form y=Mx+b

Mathematics
1 answer:
GuDViN [60]3 years ago
5 0
ANSWER: Y=-2x-6

EXPLANATION:
(2- -8)/(-4-1)= 10/-5= -2

2=-2(-4) +b
2= 8 + b
b=-6
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Solve the equation on the<br> interval [0, 27r).<br> 4(sin x)2 - 2 = 0
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x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill

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4 0
1 year ago
F(x)=x^2+2x-1 <br>find f(-3)​
emmasim [6.3K]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
What is the value of v? 45(v−7)=2
luda_lava [24]
<span>45(v−7)=2
45v - 315 = 2
45v = 317
v = 317/45
v = 7 2/45 (7 and 2/45)</span>
7 0
3 years ago
Read 2 more answers
Simplify (3v5+8v3−10v2)−(−12v5+4v3+14v2) . Write answer in standard form.<br> ​<br> ​
Tatiana [17]

Answer:

15v^5+4v^3-24v^2

Step-by-step explanation:

Distribute the Negative Sign:

=3v5+8v3−10v2+−1(−12v5+4v3+14v2)

=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)

=3v5+8v3+−10v2+12v5+−4v3+−14v2

Combine Like Terms:

=3v5+8v3+−10v2+12v5+−4v3+−14v2

=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)

=15v5+4v3+−24v2

Answer:

=15v5+4v3−24v2

Hope this helps! :)

5 0
2 years ago
What is the first step to verify that the following identity is true?
umka2103 [35]

Step-by-step explanation:

this right ans according to your question

8 0
2 years ago
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