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Dimas [21]
4 years ago
15

Which table does not represent a proportional relationship?

Mathematics
2 answers:
expeople1 [14]4 years ago
8 0

Answer:

the first one

Step-by-step explanation:

i just did it on edgenuity

OleMash [197]4 years ago
7 0
Answer: the third one

Explanation: 12:2, 18:3, but 22 isn’t equivalent to 4
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dem82 [27]
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3 0
3 years ago
DEFFERENTIATE X^sinx
inna [77]

Answer:

y = x^(sin(x))

y = e^(SIN(x)*LN(x))

y' = (COS(x)·LN(x) + SIN(x)/x)*e^(SIN(x)*LN(x))

y' = (COS(x)·LN(x) + SIN(x)/x)*x^(SIN(x))


4 0
3 years ago
Read 2 more answers
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
For a moving object, the force acting on the object varies directly with the objects acceleration. When the force of 63 N acts o
Serjik [45]

Answer:

49N

Step-by-step explanation:

Step one

Given

When the force of 63 N acts on a certain object

the acceleration of the object is 9/ms^2

Firstly, we need to calculate the mass m

F=ma-------1

m= F/a

m= 63/9

m= 7kg

Step two:

Also, if the acceleration of the object becomes 7 m/s^2

then the force

Note: the mass remains the same= 7kg

F=ma

F=7*7

F= 49N

4 0
2 years ago
Describe the graph of y &gt; mx, where m &gt; 0
Dennis_Churaev [7]

The graph of y > mx, where m > 0, consists of a dashed line and a shaded half plane. The line has a positive slope and passes through the origin. The shaded half plane is above the line.

6 0
3 years ago
Read 2 more answers
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