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Dovator [93]
4 years ago
8

An apple falls from a tree. it hits the ground at a speed of about 8 m/s . what is the approximate height of the tree?

Physics
2 answers:
svlad2 [7]4 years ago
8 0
V=sqrt(2gh)
8m/s=sqrt(2*9.8m/s^2*h)
h=3.3m
timofeeve [1]4 years ago
3 0

The motion of the apple is a free fall motion, so it is a uniformly accelerated motion. Therefore, we can use the following equation:

v^2-u^2 =2gh

where

v=8 m/s is the speed of the apple when it hits the ground

u=0 is the initial speed of the apple

g=9.81 m/s^2 is the free-fall acceleration

h is the height from which the apple has fallen


Substituting data and rearranging the equation, we can find the height of the tree, h:

h=\frac{v^2}{2g}=\frac{(8 m/s)^2}{2(9.81 m/s^2)}=3.26 m

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