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Feliz [49]
3 years ago
6

train travels 1/4of its total distance over half of its time with a constant velocity of 5m/s. calculate the average velocity​

Physics
1 answer:
Katarina [22]3 years ago
3 0

Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is

v (ave) = D/T

We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means

D/4 = (5 m/s) (T/2)

⇒   5 m/s = 1/2 D/T

⇒   v (ave) = D/T = 10 m/s

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The Answer is A!

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4 years ago
Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
maksim [4K]
The 7.5 is a 100 times stronger than the 5.5 . The 100 comes from the increase in scale from 5.5 to 7.5 which is an increase of two so you multiply the strength of the weaker earthquake 10^7-5=10^2=100 and that gives you the strength of the stronger earthquake!
7 0
3 years ago
A person who weighs 509,45 N empties her lungs as much as
Masja [62]

Answer:

The weight of the girl = 1045.86 kg/m³

Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

⇒ D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

<em>Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N</em>

<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

<em></em>

7 0
4 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
What other theory does the author compare to the Big Bang to?
sveta [45]

Answer:

The two Russian authors based their exposition on what they called the Friedmann theory of a singular beginning of the universe, referring throughout to the “theory of the hot universe” as an alternative to the hot Big Bang theory.

7 0
3 years ago
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