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True [87]
3 years ago
9

How high up is a 3.00 kg object that has 300.j of energy

Physics
2 answers:
loris [4]3 years ago
8 0

Answer:

10.20meters

Explanation:

insens350 [35]3 years ago
7 0

Answer:

10.2 m

Explanation:

The formula for potential energy is

PE=mgh

Let's plug in the given values into the equation

300 J = 3.00 kg*9.8m/s²*h

We're assuming that the object is on Earth and has a gravitational acceleration of 9.8m/s²

300J = 29.4 N * h

h = 10.2 m

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Answer:

Explanation:

In order to calculate the change of any quantity you must substract the initial value of that quantity from the final value of the same quantity.

The concept of momentum is defined as,

Momentum = mass×velocity

So we calculate the change of momentum as,

Momentum change = final momentum - initial momentum

= mv - mu =m(v-u)

Where v = final velocity

u = initial velocity

m = mass of the object

So to calculate the momentum change of the car,

Change in momentum of the car = 1000×(8-1) = 1000×7 = 7000 Ns

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3 years ago
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Answer:

Option (D)

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This process appears to be bending of light. When a light passes from a lighter to a denser medium, it gets bend towards the normal. And when the light passes from a denser to a lighter medium then it gets bend away from the normal.

Thus, the correct answer is option (D).

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