- The net force is greatest at the position of maximum displacement
- The net force is zero when at the equilibrium position
Explanation:
The motion of a spring is a Simple Harmonic Motion, in which the displacement of the end of the spring is given by a periodic function of the form

where A is the amplitude (the maximum displacement), and
the angular frequency of the motion.
We can analyze the net force acting on the spring by looking at Hooke's law:

where
F is the net force
k is the spring constant
x is the displacement
From the equation, we notice immediately that:
- The net force is the greatest when the displacement x is the greates, so at the position in which the spring has maximum compression or stretching
- The net force is zero when the displacement x is zero, so when the spring crosses the equilibrium position
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Vector ' W ' best and there ya go
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
Answer: b
Explanation: the two pieces will repel as both have obtained a static charge.