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wolverine [178]
3 years ago
8

Two projectiles are launched with the same initial speed from the same location, one at a 30° angle and the other at a 60° angle

with the horizontal. They land at the same height at which they were launched. If air resistance is negligible, how do the projectiles’ respective maximum heights, H30 and H60 , and times in the air, T30 and T60 , compare with each other?
Physics
1 answer:
DanielleElmas [232]3 years ago
7 0

Answer:

Explanation:

Given

launch angle \theta _1=30^{\circ}

\theta _2=60^{\circ}

\theta _1 and \theta _2 are complimentary angles so range for both of them is same

H_{max}=\frac{u^2(\sin \theta )^2}{2g}

H_{30}=\frac{u^2(\sin 30)^2}{2g}

H_{30}=\frac{u^2}{8g}

time of flight =\frac{2u\sin \theta }{g}

t_{30}=\frac{u}{g}

For \theta =60^{\circ}

H_{60}=\frac{u^2(\sin 60)^2}{2g}

H_{60}=\frac{3u^2}{8g}

t_{60}=\frac{2u\sin 60}{g}=\frac{\sqrt{3}u}{g}

H_{60}=3\times H_{30}

t_{60}=\sqrt{3}\times t_{30}

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