In the scenario above, James can we create a function to combine the two by f ( x ) = 8 x + 118.
<h3>What is the simplification about?</h3>
In the question above, to be able to create a function, we have to show that;
s ( x ) = 102
a ( x ) = 8 ( x + 2 )
So, a function that combines the two will be:
f ( x ) = s ( x ) + a ( x ) = 102 + 8 ( x + 2 ) =
= 102 + 8 x + 16
Therefore f ( x ) = 8 x + 118
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Answer:
f(0)= 3-2^0 --> 3-1 =2
f(-1)= 3 - 2^-1 --> 3 - 1/2 -->5/2 = 2,5
Step-by-step explanation: F(0) means if x=0 so the first you just take x and replace it with 0 and the second you replace x by -1.
Something that is elevated by 0 is always going to be 1
Hope this make sense :)
Answer:
si muy bien y tu?
Step-by-step explanation:
<span>The correct answer is n</span>²<span>+3.
Explanation<span>:
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2.
Since these are the same, this sequence is quadratic.
We use (1/2a)n</span></span>²<span><span>, where a is the second difference:
(1/2*2)n</span></span>²<span><span>=1n</span></span>²<span><span>.
We now use the term number of each term for n:
4 is the 1st term; 1*1</span></span>²<span><span>=1.
7 is the 2nd term; 1*2</span></span>²<span><span>=4.
12 is the 3rd term; 1*3</span></span>²<span><span>=9.
19 is the 4th term; 1*4</span></span>²<span><span>=16.
28 is the 5th term: 1*5</span></span>²<span><span>=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n</span></span>²<span><span>+d;
in our case, 1n</span></span>²<span><span>+d, and since d=3, 1n</span></span>²<span><span>+3.</span></span>
Answer:
5/6
Step-by-step explanation: