the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
{2, 4}
Step-by-step explanation:
Intersection is the elements that two or more sets have in common. In A and B, they share {2, 4} in common.
Answer:
500 and 700
Step-by-step explanation:
It says '7 hundreds' referring to 700. and it then say the second number has 2 fewer, two fewer hundreds is 200. so the two numbers are 500 and 700.
It depend on what d was. anything in Q3 can work for the reflection and both x and y are negative, you can say that for sure. for the actual point D, anything in Q4. in Q4 x is positive and y is negative. if d is (3,-3) then it's reflection is (-3,-3)
