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valentina_108 [34]
4 years ago
9

(a) An angle measures 39º. What is the measure of its complement?

Mathematics
1 answer:
Basile [38]4 years ago
8 0

Answer:

a) 51 degrees

b) 134 degrees

Step-by-step explanation:

39+51=90

46+134=180

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Answer:

Testigos de primera mano

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Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

8 0
2 years ago
What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

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3 years ago
QUESTION 3 I [12] A student must answer a multiple-choice question with five possible answers. He knows the correct answer with
wel

The probability that the student does not know the answer but he randomly guesses it is 0.146025

<h3>How to solve for the probability of having a correct guess</h3>

The question has only one right answer out of 5 choices.

Probability he answers incorrectly:

1 - 0.55 * 4/5

= 0.45 * 0.8

= 0.36

Probability he does not know answer but answers the question correctly

\frac{(1-0.55)\frac{1}{5} }{0.55+(1-0.55)\frac{1}{5} }

= 0.09/0.55+0.09

= 0.140625

Read more on probability here: brainly.com/question/24756209

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2 years ago
Slope = -2/3, passes through (6, -2)
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Y-(-2)= -2/3(x-6)
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