Answer:
Step-by-step explanation:
<u><em>The complete question is</em></u>
What is the midpoint of the segment shown below?
(1,-1) (4, -6)
we know that
The formula to calculate the midpoint between two points is equal to
we have
substitute the given values
The slopes of both lines are equal so they're parallel.
Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
The equivalent expression is 12x+30y and the area is 156 ft².
Using the distributive property, we have
6(2x+5y)
6*2x+6*5y
12x+30y
If x=3 and y=4,
12*3+30*4
36+120
156
Answer:
Here is the complete question (attachment).
The function which represent the given points are 
Step-by-step explanation:
We know that a general exponential function is like,
We can find the answer by hit and trial method by plugging the values of 
coordinates.
Here we are going to solve this with the above general formula.
So as the points are 
then for 
Can be arranged in terms of the general equation.
...equation(1) and 
...equation(2)
Plugging the values in equation 2.
We have
![\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bb%7D%20b%5E4%3D128%2C16%5Ctimes%20b%5E3%3D128%2Cb%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B128%7D%7B16%7D%7D%20%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
Plugging 
in equation 1.
We have 
Comparing with the general equation of exponential 
and
So the function which depicts the above points =
From theoption we have B as the correct answer.
