What is the unit value of the 3 in 432

Mathematics

2 answers:

mart [117]3 years ago

8 0

It is in the tenth place

ipn [44]3 years ago

8 0

If you separate them it would be 400 + 30 + 2 , so your unit value of the 3 would be 30.

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Help me plsss! Thank you

Brrunno [24]

You want to calculate the interest on $3020 at 5% interest per year after 6 6 month period(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $3020.00.

r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

t is the time involved, 6....6 month period(s) time periods.

Since your interest rate is "per year" and you gave your time interval in "6 month period(s)" we need to convert your time interval into "year" as well.

Do this by dividing your time, 6- 6 month period(s), by two (2), since there's two 6-month periods in 1 year.

So, t is 3....year time periods.

To find the simple interest, we multiply 3020 × 0.05 × 3 to get that:

The interest is: $453.00

Usually now, the interest is added onto the principal to figure some new amount after 6 6 month period(s),

or 3020.00 + 453.00 = 3473.00. For example:

If you borrowed the $3020.00, you would now owe $3473.00

If you loaned someone $3020.00, you would now be due $3473.00

If owned something, like a $3020.00 bond, it would be worth $3473.00 now.

4 0

3 years ago

Read 2 more answers

4. x^2+13x=-42

Mrrafil [7]

$x^2+13x=-42\ \ \ |+42\\\\x^2+13x+42=0\\\\x^2+6x+7x+42=0\\\\x(x+6)+7(x+6)=0\\\\(x+6)(x+7)=0\iff x+6=0\ \vee\ x+7=0\\\\x=-6\ \vee\ x=-7$

Anaswer: <span>a. x = -6 or x = -7</span>

8 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.