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9966 [12]
3 years ago
8

Which equations represent hyperbolas?

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer:

The correct options are 2 and 5.

Step-by-step explanation:

The general form of conics is

Ax^2+Bxy+Cy^2+Dx+Ey+F=0

This equation represents the hyperbola if

B^2-4AC>0

compare the given equations with the general equation.

In option 1,

A=2,B=0,C=2,D=16,E=14,F=-9

B^2-4AC=(0)^2-4(2)(2)=-16

This equation does not represents a hyperbola.

In option 2,

A=2,B=0,C=-5,D=4,E=-10,F=57

B^2-4AC=(0)^2-4(2)(-5)=40>0

This equation represents a hyperbola.

In option 3,

A=-1,B=0,C=-7,D=5,E=2,F=-81

B^2-4AC=(0)^2-4(-1)(-7)=-28

This equation does not represents a hyperbola.

In option 4,

A=0,B=0,C=-2,D=1,E=4,F=15

B^2-4AC=(0)^2-4(0)(-2)=0

This equation does not represents a hyperbola.

In option 5,

A=-1,B=0,C=3,D=12,E=7,F=11

B^2-4AC=(0)^2-4(-1)(3)=12>0

This equation represents a hyperbola.

Therefore the correct options are 2 and 5.

bezimeni [28]3 years ago
4 0
Try this option:
1. Common view of hyperbola equation is: 
\frac{x^2}{a} - \frac{y^2}{b} =1 \ , where  \ a,b-numbers
2. hyperbolas are: 2x²+4x-5y²-10y+57=0 and -x²+12x+3y²+7y+11=0.
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Derive the equation of the parabola with a focus at (−5, −5) and a directrix of y = 7
WARRIOR [948]

Answer: The equation of the parabola is (x+5)^2=-24(y-1).

Explanation:

It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.

The standard form of the parabola is,

(x-h)^2=4p(y-k)

Where y=k-p is directrix and (h,k+p) is the focus.

Since focus is given,

(h,k+p)=(-5,-5)

On comparing,

h=-5

k+p=-5      .... (1)

The directrix is y=7.

k+p=7       .... (2)

Add equation (1) and (2),

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Put this value in (1).

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Therefore, the equation of parabola is (x+5)^2=-24(y-1).

8 0
3 years ago
Read 2 more answers
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