Answer:
Step-by-step explanation:
length=1 m
base of triangle=10 m
height=5m
volume= 1/2×10×5×1=25 m cube.
slant height l=√(5²+5²)=√50=5√2
slant surface area=2[5√2×1]=10√2
area of front and back=2×1/2(10×5)=50
total surface area=50+10√2≈50+14.14≈64.14 m²
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
It would be great if you would provide the image itself. I will totally answer your question.
To do this, simply add the 2 functions-as it says:
(2x+1) + (-3x+4)
2x+1-3x-4
-x-3
Your answer is -x-3
