The doughnut because it contains carbohydrates
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype . A normal man will have the genotype . When the 2 marries:
x = It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x = 50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
The outward appearance of a trait is called a phenotype.
The phenotype of the organism can differ from the genotype(genetic makeup of a trait). This can happen if one half of the trait is dominant over the other half, creating the trait the dominant side 'codes' for.
I believe the answer is delta.