A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average v
elocity of the dog from A to C?
1 answer:
we could take a peek at this scenario with say

now, keeping in mind that the average rate of change is really just the slope, then

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Answer:
6(9r-7)
Step-by-step explanation:
54r–42
Both 54 and 43 can be divided by 6
54/6 =9 and 42/6 =7
6*9r - 6*7
Factor out the 6
6(9r-7)
Answer:
2(x+5)*(x-9)
Step-by-step explanation:
The answer should be
_
.16
Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
-78=-78
So, the fraction of races that he won was:

: you need ti divide the number of occurrences by the number of possibilities.
We can simplify this:

.
When we write it in decimals until the closest place, it's:
0.167 or 16.667%