The cinematic equation is:
h (t) = (1/2) * a * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height
Substituting values:
h (t) = (1/2) * (- 32) * t ^ 2 + (0) * t + 9
h (t) = - 16t ^ 2 + 9
For t = 0.2 we have:
h (0.2) = - 16 * (0.2) ^ 2 + 9
h (0.2) = 8.36 feet
To touch the ground we have:
-16t ^ 2 + 9 = 0
16t ^ 2 = 9
t = root (9/16)
t = 0.75 s
Answer:
The height of the cherry after 0.2 seconds is:
h (0.2) = 8.36 feet
the cherry hits the ground at:
t = 0.75 s
Graph those points given, in a cartesian plane grid,
that is, an x,y axis grid
and try to make a straight line from the leftmost, to
the rightmost, they don't really line up as a straight
line, so... try to draw a line that will cover "most of
the points", there will be a couple or so "outliers",
the line that "covers most of the points" is so-called
"best-fit" line, so, using that line, try to get what
"y" is, when x = 3
Y = mx + b
slope(m) = 6
(-3,5)...x = -3 and y = 5
now we sub and find b, the y int
5 = 6(-3) + b
5 = -18 + b
5 + 18 = b
23 = b
so ur equation is : y = 6x + 23
Answer:
1/2 or 0.5
Step-by-step explanation:
1 odd
2
3 odd
4
5 odd
6
This is 3/6 options , or 1/2
