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3 years ago

5

What is the point of intersection for the lines x=3 and y=-2

1 answer:

drek231 [11]3 years ago

4 0

The POI is (3,-2). The two equations are simply straight lines

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1. what is the equation of a line that has an x-intercept of 2 and a y-intercept of 8

Phoenix [80]

Answer:

B

Step-by-step explanation:

x- intercept = 2 .So, Coordinate(2 , 0)

y-intercept = 8 . So, Coordinate (0, 8)

$Slope = \frac{8-0}{0-2}\\\\=\frac{8}{-2}\\\\=-4$

Slope y-intercept form: y = mx + b {Here, b is y-intercept}

y = -4x + 8

8 0

3 years ago

I am so lost, please help

skelet666 [1.2K]

Answer:

$u=\frac{9}{t}-\frac{1}{2} a t$

Step-by-step explanation:

Step 1: Given equation: $9=\frac{1}{2} a t^{2}+u t$

To get u, by subtraction equality property subtract both sides of the equation by $\frac{1}{2} a t^{2}$ .

$\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}$

$\Rightarrow 9-\frac{1}{2} a t^{2}=u t$

Step 2: By division equality property, divide both sides of the equation by t.

$\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}$

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$ .

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$ .

7 0

3 years ago

Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

7 0

3 years ago

Find the measure of <2.

iVinArrow [24]

Should be 30 as well

5 0

3 years ago

Read 2 more answers

7x ^4 minus 5x ^4 =

lapo4ka [179]

Answer:

2x^{4}

Step-by-step explanation:

You would subtract 7 and 5 and you would leave the exponent so it would be 2x^{4}

8 0

3 years ago

Read 2 more answers