((x+2)(x+2))-((x-5)(1))=A
x^2+4x+4-x+5=A
x^2+3x+9=A
Answer:
x^2+y^2=16
Step-by-step explanation:
x^2+y^2=r^2 is the mother function of the equation of a circle centered at r with radius r
since r is defined to be 4 and 4^2 is 16 therefore, the equation would then be
x^2+y^2=16
the function f(x) is increasing.
looking at the domain -2 < x < -1, we can see that the function f(x) = 2^x (labeled in blue) has an increasing slope.
The numerator factors as (t-8)(t+4), so the whole thing is (t-8)(t+4)/(t-8). Now we can cancel the t-8 AS LONG as t isn't equal to 8, otherwise, we are canceling a zero from both numerator and denominator which is invalid. What is left is t+4.
So your choice was right.
Answer:
x = 4
Step-by-step explanation:
(6x - 3)° = (2x + 13)° are vertical angles that equal each other get x by itself and solve for x.
(6x - 3)° = (2x + 13)°
6x - 2x = 13 + 3
4x = 16
x = 4
Substitute x for the angles.
(6x - 3)° = ?
(6*4 - 3)° = ?
(24 - 3)° = 21°
(2x + 13)° = ?
(2*4 + 13)° = ?
(8 + 13)° = 21°
