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sweet-ann [11.9K]

3 years ago

9

A school psychologist at a large high school took a random sample of 16 students and asked how much sleep they get on a typical

weekend night. The sample data were roughly symmetric with a mean of 8.75 hours and a standard deviation of 1.5 hours

1 answer:

puteri [66]3 years ago

7 0

Answer:

8.75 +/- 0.657

Step-by-step explanation:

You might be interested in

A wooden flooring strip is 20 1/2 inches long. If you cut off 4 3/4 inches from one end what will be the new length of the strip

KonstantinChe [14]

Length of wooden flooring strip = $20\frac{1}{2}$ or $\frac{41}{2}$

Length of strip cut off = $4\frac{3}{4}$ or $\frac{19}{4}$

So, the new length of the strip will be=

$\frac{41}{2}- \frac{19}{4}$

= $\frac{82-19}{4}=\frac{63}{4}$

Hence, the new length of the flooring strip will be $\frac{63}{4}$ inches and in mixed fraction it will be $15\frac{3}{4}$ inches.

8 0

3 years ago

Please help and show your work for both a. and b.

bixtya [17]

Answer:

a.

C = 5/8 (F - 32)

C × 8 = 5/8 × 8 (F - 32)

8C = 5(F - 32)

$\frac{8C}{5} = \frac{5(F - 32)}{5}$

$\frac{8C}{5}$ = F - 32

$\frac{8C}{5} + 32$ = F - 32 + 32

$\frac{8C}{5} + 32$ = F

b.

C = 22

F = $\frac{8C}{5} + 32$

F = $\frac{8(22)}{5} + 32$

F = $\frac{176}{5} + 32$

F = 35.2 + 32

F = 67.2

6 0

3 years ago

Find the value of a that makes m||n

Brut [27]

The value of x that makes m║n is 40°

<h3>Line of transverse on parallel lines: </h3>

In geometry, the line that intersects two straight lines at distinct points is known as a transversal.

<h3>Corresponding angles: </h3>

The angles that are formed when two parallel lines are intersected by a third line i.e a transversal are corresponding angles.

Note:

Two corresponding angles are formed by a transversal with two parallel lines that are equal

Here we have

The angle made by the intersecting line with line m is 120°

And the angle made by the same line with line n is 3x°

Let us assume that m║n

From above observations

The given angle are corresponding angles

=> 3x° = 120°

=> x° = 40°

Therefore,

The value of x that makes m║n is 40°

Learn more about the Line of transverse at

brainly.com/question/11592045

#SPJ1

6 0

1 year ago

Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)

muminat

Answer:

The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = $\frac{-5}{2}$ x + $\frac{12}{2}$

Or, y = $\frac{-5}{2}$ x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = $\frac{-5}{2}$

Again,

The other line if passing through the points (- 2 , 3 ) And is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So, M = m = $\frac{-5}{2}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = $\frac{-5}{2}$ × ( - 2 ) + c

or, 3 = $\frac{10}{2}$ + c

Or, 3 = 5 + c

∴ c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope $\frac{-5}{2}$ and passing through points ( -2 , 3)

y = $\frac{-5}{2}$ x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And is perpendicular to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So, M' × m = - 1

Or, M' × $\frac{-5}{2}$ = - 1

Or, M' = $\frac{-1}{\frac{-5}{2}}$

Or, M' = $\frac{2}{5}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = $\frac{2}{5}$ × ( - 2 ) + c'

or, 3 = $\frac{- 4}{5}$ + c'

Or, 3 × 5 = - 4 + 5× c'

∴ 5 c' = 15 + 4

or, 5 c' = 19

Or, c' = $\frac{19}{5}$

So, The equation of line with slope $\frac{2}{5}$ and passing through points ( -2 , 3)

y = $\frac{2}{5}$ x + $\frac{19}{5}$

y = $\frac{2 x + 19}{5}$

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0

3 years ago

Write ten subtraction problems with 6 as the difference?

gayaneshka [121]

1 - 2 = 1 3 - 4 = 1 5 - 9 = 4 9 - 9 = 0 7 - 14 = 7 21 - 0 = 21 8 - 12 = 5 4 - 85 = 81 x is 8 and z is 5. x - z = 3 d is 2 and 8 is w and 17 is y. d - w - y = 7

5 0

3 years ago