Answer:
The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>
Step-by-step explanation:
The given data are;
Bakery A
<em> </em>= 1,880 cal
s₁ = 148 cal
n₁ = 10
Bakery B
<em> </em>= 1,711 cal
s₂ = 192 cal
n₂ = 10
df = n₁ + n₂ - 2
∴ df = 10 + 18 - 2 = 26
From the t-table, we have, for two tails, 
= 1.706
≈ 178
Therefore, we get;
Which gives;
Therefore, by rounding to the nearest integer, we have;
The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289
Answer:
A) p(male)=20/30=2/3
b) p(female) = 10/30=1/3
c) p(11th grade) = 12/30=2/5
d) p(12th grade) = 18/30 = 3/5
e) p( girl and in 11th grade) =4/30=2/15
F) p(12 th grade and female) = 6/30 = 1/5
g) p(male and in 12th grade) = 12/30 = 2/5
h) p(male and if we know the student is female) = 0 if we know the student is male then she can't be male again. these are mutuallyinclusive event and they can't occur at once.FOR more details and solutions,clarification and more explanation contact me via my g mail at [email protected] and I will keep in touch....please leave your comment in thisg mail which is my tutor g mail account please.
The answer is 900 because 20×9=180 and just multiply 180×5 and that equals 900.
Use Picture Math, i cant type in the other cause brainly doesn't accept it but it is Ga_thMath. (u)
Answer:
ahhh you didnt have to !!
Step-by-step explanation:
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