What is another name for mathematical rules

4xy-3x+8y2-6y 8y-6 please help someone thank you

avanturin [10]

Answer:

x=6, y=2.5

Step-by-step explanation:

6 0

3 years ago

HELPPPPPP what number would you add to -8 to make 0

MrMuchimi

Hello!

your answer is: 8

-8 is just 8 below zero, so adding 8 would bring it back to zero.

for example, 0 - 8 = -8, therefore: -8 + 8 = 0

I hope this helps, and have a nice day!

3 0

3 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

Solution:

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$

As $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ , so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0

3 years ago

What would 10/7 look like on a number like

Elanso [62]

Answer:

It would look as if it's close to 1 1/2 but not quite.

5 0

3 years ago

Read 2 more answers

Please help me with this question

swat32

Answer:

<h3>• y is 10.9</h3><h3>• theta is 65.4°</h3><h3>• Alpha is 24.64°</h3><h3>• sin theta is 10.9/12</h3><h3>• COS theta is 5/12</h3><h3>• tan theta is 10.9/5</h3><h3>• csc theta is 12/10.9</h3><h3>• ces is 12/5</h3><h3>• cot theta is 5/10.9</h3>

Step-by-step explanation:

<h3>Solution 1</h3>

Using the Pythagorean theorem

c²= a² + b², where c is the hypotenuse , a And b are the sides.

12² = y² + 5²

144 = y² + 25

144 - 25 = y²

√119 = √y²

10.9 = y

<h3>Solution 2</h3>

Using SOH-CAH-TOA

COS theta = Adjacent/Hypothesis

COS theta = 5/12

COS theta = 0.417

theta = COS-1 0.417

theta = 65.4°

<h3>theta is 65.4°</h3>

<h3>Solution 3</h3>

We are dealing with right triangle and it sum is 90.

To find Alpha subtract theta for 90

Alpha = 90 - 65.4 = 24.64°

<h3>Therefore Alpha is 24.64°</h3>

<h3>Solution 4</h3>

Using SOH-CAH-TOA

sin theta = opposite/ hypotenuse

sin theta = 10.9/12

<h3>sin theta is 10.9/12</h3>

<h3>Solution 5</h3>

Using SOH-CAH-TOA

COS theta = Adjacent/Hypothesis

COS theta = 5/12

<h3>COS theta is 5/12</h3>

<h3>Solution 6</h3>

Using SOH-CAH-TOA

tan theta = opposite/adjacent

tan theta = 10.9/5

<h3>tan theta is 10.9/5</h3>

<h3>Solution 7</h3>

csc theta is the reciprocal of sin theta

csc theta = 12/10.9

<h3>csc theta is 12/10.9</h3>

<h3>solution 8</h3>

ces theta is the reciprocal of COS theta.

ces theta = 12/5

<h3>Solution 9 </h3>

cot theta is the reciprocal of tan theta

cot theta = 5/ 10.9

<h3>cot theta is 5/10.9</h3>

6 0

2 years ago

Read 2 more answers