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tankabanditka [31]

3 years ago

10

459 randomly selected lightbulbs were tested in a laboratory 291 lasted more than 500 hours find a point estimate of the true pr

oportion of all lightbulbs in that last more than 500 hours

1 answer:

BARSIC [14]3 years ago

4 0

291:459 or 291/459 it is the amount lasted to the total amount

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Write the quadratic equation in standard form:<br> 7x + 8 + 2x2<br> 2x + 1 + x2

JulsSmile [24]

Answer:

$3x^2 + 9x +9$

Step-by-step explanation:

Given

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Required

The result in standard form

We have:

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Remove brackets

$7x + 8 + 2x^2 + 2x + 1 + x^2$

Collect like terms

$7x+ 2x + 8 + 1 + 2x^2+ x^2$

$9x + 9+ 3x^2$

The standard form of a quadratic equation is:

$ax^2 + bx + c$

So, we have:

$9x + 9+ 3x^2$

$3x^2 + 9x +9$

5 0

2 years ago

If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?

Varvara68 [4.7K]

1. Find the centre of the circle or the midpoint of the two numbers
(6-6/2}, (-2+6/2)
(0, 2)
2. Find radius using the distance formula
√<span>(6 - 2)² + (-6 - 0)²
</span>√4² + (-6)²
√16 + 36
√52
r = 7.21
3. Plug in
x² + (y - 2)² = 52

So it is option D 99% sure

6 0

2 years ago

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Simplify. (x−5)(x^2−2x−6)<br>please also explain how you got your answer. -thanks

jonny [76]

I really hope this helps

4 0

2 years ago

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What is the value of r of the geometric series n=11.3(0.8)n-1

jeyben [28]

the value of r of the geometric series n=11.3(0.8)n-1

$an=11.3(0.8)^{n-1}$

General formula for nth term of any geometric series is $a_n=a_1(r)^{n-1}$

Here 'r' is the common ratio

a_1 is the first term of the series

Now we compare the given formula with general formula

Compare $an=11.3(0.8)^{n-1}$ with $a_n=a_1(r)^{n-1}$

The value of r= 0.8

6 0

2 years ago

WILL GIVE BRAINLIEST A set of numbers is shown:

ad-work [718]

10 and 15 dear^^ 5(15) + 3(15) =28

4 0

2 years ago