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RoseWind [281]
3 years ago
13

Pls help me here Look at the picture help!!

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

x=13.5

Step-by-step explanation:

that is my answer

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Tyeewants to buy disposable masks for his family. Blue masks cost $1.50and greenmasks cost $2.50. He has $45to spend and wants t
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find the equation of the line using the point slope formula. write the final equation using the slope intercept for thr x-interc
aleksley [76]

we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).


\bf \stackrel{x-intercept}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{0})}\qquad  (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-0}{-2-1}\implies \cfrac{9}{-3}\implies -3 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-0=-3(x-1) \\\\\\ ~\hspace{10em}y=-3x+3

5 0
3 years ago
Express the following pattern as an algebraic expression: 88, 75, 62, 49. Use “n” for the term number.
Ostrovityanka [42]

Answer:

-13n + 101

Step-by-step explanation:

88, 75, 62, 49. = -13  -13 -13 = -13n + 101  (as 88+13 = 101)

5 0
3 years ago
Read 2 more answers
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

1000=P(1+\frac{0.06}{0.5})^{0.5*6}

1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

P\approx 712

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0
3 years ago
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