If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
There are 
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are 
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's 
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
Answer:
<h2>V = 729</h2>
Step-by-step explanation:
The formula of a volume of a cube with an edge <em>a</em>
<h3>
V = a³</h3>
We have <em>a </em>=<em> </em>9 . Substitute:
<h3>V = 9³ = 9 · 9 · 9 = 729</h3>
