Box and Whisker Plot?!!! Help pls !!!!

Plz I really need help with this problem Find the are of the shaded region

Nat2105 [25]

Answer:

$379.69 \: {ft}^{2}$

Step-by-step explanation:

Area of the shaded region = Area of the square with side 25 ft - Area of the semicircle with radius (25/2) = 12.5 ft.

$= {(25)}^{2} - \frac{1}{2} \times \pi \times {(12.5)}^{2} \\ \\ = 625 - \frac{1}{2} \times 3.14 \times 156.25 \\ \\ = 625 - 245.3125 \\ \\ = 379.6875 \: {ft}^{2} \\ \\ = 379.69 \: {ft}^{2}$

8 0

3 years ago

James is fencing off a triangular region for his cats to play in. From the first fence post, he walks 13 meters in a straight li

GenaCL600 [577]

You can use Heron's formula to do this

Area of triangle = sqrt[ s(s-a)(s-b)(s-c) ] where s = half the perimeter of the triangle =
1/2 * 13+5+9 = 13.5
so required area = sqrt [ (13.5)(13.5-13)(13.5-5)(13.5-9)]
= 16.1 square meters

4 0

3 years ago

Can someone help me please on number 5

Kamila [148]

Answer:

Hank earns $180

Step-by-step explanation:

If you multiply $12 × 15 you will get $180

8 0

3 years ago

5p-14=8p+4=. show work please

Ainat [17]

No Problem!
5p-14=8p+4
I assume this is the whole problem set up properly, so now, lets subtract the left side by 5p, and then the right side.
-14=3p+4
As you can see, the 5p cancels out on the left side, and the p leftover is what 8p-5p equals.

Now, subtract both sides by 4.
-18=3p
Now, simply divide both sides by 3 to equal
p= -6
The reason we do the divide and multiplying last is because doing it first would only make it much harder.
This is the simplest way I know of to do it. If you don't understand, just ask me.
Hope it helped!

7 0

3 years ago

Read 2 more answers

Which statement correctly compares the function shown on this graph with

NARA [144]

The given highest power of x in the given function, y = 4·x + 2, is 1,

therefore, the graph of the function is a straight line.

The statement that correctly compares the function shown on the graph

with the function; y = 4·x + 2 is; C. The function shown on the graph has a

smaller rate of change but a higher starting point.

Reasons:

The given function is; y = 4·x + 2

Comparing with the equation for a straight line; y = m·x + c, we have;

The rate of change or slope, m = 4

The y-intercept, starting point, c = 2

Two points on the function shown on the graph are; (0, 4), and (-2, -2)

The slope of the given graph is therefore;

$m = \dfrac{4 - (-2)}{0 - (-2) } = \dfrac{6}{2} = 3$

The rate of change of the graph, m = 3

The equation of the graph is therefore;

y - 4 = 3·(x - 0)

Which gives;

y = 3·x + 4

The y-intercept, starting point of the graph, is therefore, c = 4

Which gives;

The function shown on the graph has a higher starting point but a smaller rate of change than the given function.

Learn more here:

brainly.com/question/18194679

7 0

2 years ago