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3 years ago

The top one I need help with

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12

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2×-1=7 <br> solve<br><br> what is it ??????

QveST [7]

Answer:

x = 4

Step-by-step explanation:

2x - 1 = 7

2x = 7 + 1

2x = 8

x = 8/2

x = 4

7 0

4 years ago

I need help in #24 plz

asambeis [7]

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6 0

4 years ago

Write given percentage as a fraction in its simplest form. 75%

ollegr [7]

Answer:

3/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Two parallel lines are cut by a transversal,

Volgvan

Answer:

also 75°

Step-by-step explanation:

the angles across each other at a crossing point of 2 lines must be equal.

so, 2 = 3.

and the angles at the crossing point with a parallel line are simply a "mirror" or rather a copy of the angles at the crossing point with the first line.

so, 2 = 3 = 6 = 7

and 1 = 4 = 5 = 8

7 0

2 years ago

Which number comes next in this series? 1/64, 1/32, 1/16, 1/8, 1/4, 1/2, ?

alexgriva [62]

This is a geometric sequence, with the first term: 1/64

The common ratio is found through the ratio of the first two terms and the second and third term.
$\frac{\frac{1}{32}}{\frac{1}{64}} = \frac{\frac{1}{16}}{\frac{1}{32}}$
$\frac{1}{32} \cdot 64 = \frac{1}{16} \cdot 32$

Since there is a common difference of 2, we can generalise this sequence to find the nth term:
$T_n = ar^{n-1}$
a is the first term, r is the common ratio, and n is the nth term in the sequence.

$T_n = \frac{1}{64} \cdot 2^{n-1}$
Substituting n = 7, we get:
$T_7 = \frac{1}{64} \cdot 2^{7 - 1}$
$T_7 = \frac{1}{64} \cdot 64$
$T_7 = \frac{64}{64} = 1$

Thus, the next term in the sequence is 1.

6 0

3 years ago