Answer:
The end of the flagpole is 50.79 ft away from the base of the pole.
Step-by-step explanation:
The problem is represented by the diagram below.
The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).
The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).
Using Pythagoras theorem, we have that:
=> 
The end of the flagpole is 50.79 ft away from the base of the pole.
A)
8^2+9^2=c^264+81=c^2
c^2=145c=sqrt 145c=12.04
B)
Pythagerean Theorum:
A^2+B^2=C^2, where C is the hypotenuse and A and B are the other legs
15^2=9^2+B^2
225=81+B^2
225-81=B^2
144=B^2 (square root both sides)
12=B
Answer:
84
Step-by-step explanation:
Plug in 9 for k.
5(9)(2) - 6
first: (9)(2) = 9 x 2 = 18
5(18) - 6
second: 5(18) = 5 x 18 = 90
last: 90 - 6 = ?
84
hope this helps
Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
