...42, -193.. thats the 4th and 5th Hope this helps
Answer:
<h2>The answer is 0.1493.</h2>
Step-by-step explanation:
In a standard deck there are 52 cards in total and there are 4 aces.
Two cards can be drawn from the 52 cards in
ways.
There are (52 - 4) = 48 cards rather than the aces.
From these 48 cards 2 cards can be drawn in
ways.
The probability of choosing 2 cards without aces is
.
The probability of getting at least one of the cards will be an ace is
.

so the slope of that line above is really -4/3, now
