Simplify this quadratic function given in vertex form into standard form by simplifying the exponents and adding like terms.
(good luck :) and mark me brainliest if you're satisfied with my answer)
Which the on the graph belownastasiopelozero
1 answer:
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Answer:
This a circle centered at the point , and of radius "3" as it is shown in the attached image.
Step-by-step explanation:
Recall that the standard formula for a circle of radius "R", and centered at the point is given by:
Therefore, in our case, by looking at the standard equation they give us, we extract the following info:
1) since the radius must be a positive number and (
) is not a viable answer.
2) for (
) to equal
3) for (
) to equal
Therefore, we are in the presence of a circle centered at the point , and of radius "3". That is what we draw as seen in the attached image.
Answer:
The steps to construct a a line parallel to another line from a point includes
1) From the given line draw a transversal through the point
2) With the compass, copy the angle formed between the transversal and the given line to the point P
3) Draw a line through the intersection of the arcs of the angle construction to get the parallel line through the point P
Step-by-step explanation:
