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Triss [41]
3 years ago
9

Which the on the graph belownastasiopelozero

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

I'm just guessing that we re the update and after we can do it now if I get a chance I would be able it was you please me to answer is D the number of the it was just wondering what time for me and my dad

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The coordinates of the vertices of the triangle are
Alecsey [184]

The area of the triangle PQR is 108 square units

<h3>How to determine the area of the triangle?</h3>

The given parameters are:

  • Height, h =  12 units
  • Base, b = 18 units

The area is then calculated using:

Area = 0.5 * base * height

So, we have:

Area = 0.5 * 18 * 12

Evaluate

Area = 108

Hence, the area of the triangle PQR is 108 square units

Read more about areas at:

brainly.com/question/24487155

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6 0
2 years ago
Read 2 more answers
Which represents the solution of –9.5 + 6x ≥ 42.1 using interval notation?
OlgaM077 [116]
Hello : 
<span>–9.5 + 6x ≥ 42.1
6x </span>≥ 42.1 + 9.5
6x ≥ 51.6
x ≥ 51.6/6
x ≥ 8.6
using interval notation: <span>[8.6  ; +∞[ </span>
5 0
3 years ago
What is the quotient of 1/2÷1/6=
Sphinxa [80]
1/2 <span>÷ 1/6 =

Divide fractions:

a x d /  b x c

 Therefore:

1 x 6 / 2 x 1 =

6 / 2 = 3

hope this helps!

</span>
3 0
3 years ago
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What are three sets of fractions that can be multiplied to get 15/56?
vredina [299]
Much more than just 3.

3 0
4 years ago
How many complex roots does the equation below have?
Maslowich

Answer:

  The number of complex roots is 6.

Step-by-step explanation:

Descartes's rule of signs tells you that the number of positive real roots is 0. The number of negative real roots will be at most 2. The minimum value of the left side will be between x=0 and x=-1, but will never be negative. Thus all six roots are complex.

_____

The magnitude of x^3 will exceed the magnitude of x^6 only for values of x between -1 and 1. Since the magnitude of either of these terms will not be more than 1 in that range, the left-side expression must be positive everywhere.

4 0
3 years ago
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