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andriy [413]
3 years ago
11

When two solvents are seperated by a semi premamble membrane, water flows

Biology
1 answer:
fomenos3 years ago
3 0
Water flows from the side of higher water potential (higher water concentration leads to higher water potential) to the side of lower water potential. 

This movement is called osmosis. Water potential means the tendency of water flowing away. The higher the water concentration the solvent/solution is, the higher the water potential is and the more likely it'll flow to the other side. 

Therefore, if one of the solvents has 10% water and the other has 50% water, water molecules will flow from the one with 50% water to the 10% one. This movement is completely natural and does not require extra energy. The net flow will stop until both sides have the same water concentration. Water still flows through both sides at that time, but no net flow. 

Note that osmosis is only the movement of water molecules, with the presence of semi-permeable membrane (which can decide what substances can go through), and the flow of down the water potential gradient. If any one of these is not applicable, the movement is not osmosis. 

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Answer:

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3 years ago
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Answer:

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3 years ago
In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of the allele a is 0. 3. What i
zavuch27 [327]

Here, given-

homozygous alleles 'a' have a frequency of 0.3.

Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.

The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.

Calculation-

p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7

Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-

p^{2} + 2pq + q^{2} =1

p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\

Thus, the individuals homozygous for the allele can be calculated by q^{2} = (0.7)^{2} \\= 0.49

Learn more about the Hardy-Weinberg equilibrium here-

brainly.com/question/16823644

#SPJ4

4 0
2 years ago
Alice goes to see a rerun of jaws (a movie about a vicious shark) a few days before she travels to florida for spring break. whi
astraxan [27]
The answer is priming

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7 0
3 years ago
Aerobic respiration produces _______ as products.
Blababa [14]
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3 years ago
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