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3 years ago

10

Gavin and Jim are marking exam papers. Each set takes Gavin 48 minutes and Jim 1 hour. Express the times Gavin and Jim take as a

ratio. Give your answer in its simplest form.

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

4:5

Step-by-step explanation:

1HR=60 MIN

48 MIN - 60MIN

48/60=4/5

4/5=4:5

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Help please :( thank u

snow_tiger [21]

Answer:

he needs to know the width!!!

Step-by-step explanation:

since length multiplied by the width equals area,

so since the length is given, the width is needed

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2 years ago

What's 18➗4.52? Plz help

xz_007 [3.2K]

If you want to calculate 18/4.52, you can do this using the following steps:

18/4.52 = 18 / 4 52/100 = 18 / 452/100 = 18 * 100/452 = 1800/452 = 450/113 = 3.98

The correct result is 3.98.

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2 years ago

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Rewrite the expression in the form z^n

olga55 [171]

Answer:

${z}^{ \frac{1}{2} }$

Step-by-step explanation:

$\huge \sqrt[5]{ {z}^{4} {z}^{ - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{4 - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{8 - 3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{5}{2} } } \\ \\ = \huge {z}^{ \frac{5}{2} \times \frac{1}{5} } \\ \\ = \huge {z}^{ \frac{1}{2} }$

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2 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

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2 years ago

a basketball coach keeps track of the points scored per game for all her players.she gives a trophy to the player with the highe

podryga [215]

The answer would be C. When you calculate the mean, it includes every number for a certain period of time into things and averages it out. The median does not average out all the numbers.

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2 years ago

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