Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)

Mathematics

1 answer:

mina [271]3 years ago

6 0

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

.. 6^2/12 -x^2/b = 1

.. 2 = x^2/b

.. b = x^2/2

If your point is (2√3, 6), then this is

.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is

.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

Step-by-step explanation:

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The hourly wages earned by 20 employees are shown in the first box-and-whisker plot below. The person earning $15 per hour quits

agasfer [191]

Answer:

<h2>The mean decreases, and the median remains the same.</h2>

Step-by-step explanation:

Remember that a box plot is made by the quartiles of the distribution, the maximum value and the minimum value. So, from a box plot we can deduct the range, the median and the interquartile range.

In this case, the median remains the same at $9.5 per hour. The median is indicated by the middle line of the box, and you can observe that it doesn't change.

Now, the range of the data set decreases from 7 to 3.

On the other hand, the mean must decrease, because data greater than $11 doesn't exist in the box plot number 2, and the mean is a central measure sensible to those changes.

Therefore, the right answer is <em>The mean decreases, and the median remains the same.</em>