Answer:
Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)
1 answer:
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Answer:
Corresponding Angles sum to 180°
Step-by-step explanation:
If a pair of parallel lines is cut by transversal that is not perpendicular to the parallel lines as shwon in the figures (attached below), then;
Four angles are acute, and four are obtuse.
- All four acute angles are equal: 2=3=6=7
- All four obtuse angles are equal: 1=4=5=8
- The sum of acute and obtuse angles is 180: for example, 1+2=180, 3+4=180, 5+6=180, 7+8=180
so the best attribute for the angle pair formed by two parallel lines intersected by a transversal is that Corresponding Angles sum to 180°.
The quotient is 0.20125.
Solution:
Divide .03220 by .16
This can be written as
To divide this, we first remove the decimal term.
To remove decimal in denominator multiply and divide by 100.
Now, divide 3.22 by 16.
The quotient is 0.20125.
The image of the long division is attached below.
