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3 years ago

Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)

Mathematics

1 answer:

mina [271]3 years ago

6 0

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

.. 6^2/12 -x^2/b = 1

.. 2 = x^2/b

.. b = x^2/2

If your point is (2√3, 6), then this is

.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is

.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

Step-by-step explanation:

You might be interested in

Please help me with this system of equations problem

LekaFEV [45]

Answer:

5x-2y=3

-3x+4y=1

5x-2y=-3x+4y+2

+2y

5x=-3x+6y+2

+3x

8x=6y+2

divide by 2

4x=3y+1

-3y+4x=1

wait so that means that -3x+4y=-3y+4x so that means that both x and y are equal so lets just say their the same

-3x+4x=1

x=1

y=1

Hope This Helps!!!

7 0

1 year ago

Helpppppppppppppppppppppppp

Genrish500 [490]

Answer:

Is none a answer?

Step-by-step explanation:

They dont have a relashionship

8 0

2 years ago

Roger is paid $50 to sell videos of a play to an audience after the play is preformed.

konstantin123 [22]

Answer:

Roger can earn $510 at most.

Step-by-step explanation:

We are given the function

Which gives the earnings of Roger when he sells v videos. Since the play’s audience consists of 230 people and each one buys no more than one video, v can take values from 0 to 230, i.e.

That is the practical domain of E(v)

If Roger is in bad luck and nobody is willing to purchase a video, v=0

If Roger is in a perfectly lucky night and every person from the audience wants to purchase a video, then v=230. It's the practical upper limit since each person can only purchase 1 video

In the above-mentioned case, where v=230, then

Roger can earn $510 at most.

3 0

2 years ago

Check my proof? Two diagonals of a parallelogram bisect each other?

SIZIF [17.4K]

Your proof is correct and very well done

6 0

2 years ago

An oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches. What is the volume of the obl

trasher [3.6K]

Oblique Cone

The volume of the oblique cone is 144.49 cubic inches , if an oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches.

Step-by-step explanation:

An oblique cone has a radius of 4 units

A height of 8.5 units

A slant length of 11.7 inches

We have to use the slant height to calculate actual base

So in a right angle triangle when two sides are given the third side is calculated by

Root (sqr(11,7) - sqr(8.5)) = 8.03 units

$\sqrt{11.7^{2} - 8.5^{2} }$

⇒ 8.03 units

Formula to calculate the volume of oblique cone,......................(1)

V = $\frac{1}{3} bh$

If r is the distance of the base of the height from the center of the circle [ this is because the base of the height is outside the oblique cone]

V = $\frac{1}{3} \pi r^{2} h$

Where r is the distance if the base of the height from the center of the circle [ this is because the base of the height is outside the oblique cone]

Here r = 8.03 - 4 = 4.03 units

Volume = $\frac{1}{3}$ × 3.14 × 4.03 × 4.03 × 8.5

Volume = 144.49 cubic inches

Hence, the volume of the oblique cone is 144.49 cubic inches , if an oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches.

6 0

2 years ago

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