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Studentka2010 [4]
3 years ago
9

Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

.. 6^2/12 -x^2/b = 1

.. 2 = x^2/b

.. b = x^2/2

If your point is (2√3, 6), then this is

.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is

.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The product of distances from the intersection of secants to the near and far intersections with the circle are the same. For a tangent, the near and far points of intersection with the circle are the same. This relation tells us ...

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_____

<em>Alternate solution</em>

If you believe x to be an integer, you can look for factors of 12 that differ by 4.

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The factors 2 and 6 differ by 4, so x=2 and x+4=6.

6 0
3 years ago
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matrenka [14]

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The ratio of the areas of two similar rectangles is 1:4. What is the ratio of the corresponding sides?
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WITCHER [35]

Answer:

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Step-by-step explanation:

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LUCKY_DIMON [66]
\boxed{\boxed{\text{ if } \dfrac{a}{b}=\dfrac{c}{d} \text{ then }a\times d=b\times c}}

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