Very confused on how to get the inside variables

FAST

sertanlavr [38]

Answer: The system consists of parallel lines

Step-by-step explanation:

Given system of lines :

$y=\dfrac13x-4$

$3y-x=-7$

Substitute $y=\dfrac13x-4$ in $3y-x=-7$ , we get

$3(\dfrac13x-4)-x=-7\\\\\Rightarrow\ x-12-x=-7\\\\\Rightarrow\ -12=-7$ , which is not true.

That means , system has no solution.

i.e. they are representing parallel lines. [Parallel lines do not intersect and hence they do not have solution.]

6 0

2 years ago

Hii darling pls help !!<3

saul85 [17]

Answer:

Hello! answer: y = 76

Because there vertical angles they Will have the same measure therefore y = 76 Hope that helps!

6 0

3 years ago

Iris weighed 5 large watermelons from her garden. Here are the weights in pounds. 17,11,21,24,22 what is the mean weight

Rufina [12.5K]

Answer:

Mean weight = 19 pounds

Step-by-step explanation:

From the question given above, the following data were obtained:

17, 11, 21, 24, 22

Number of data (n) = 5

Mean weight =?

The mean of a set of data is the value obtained by adding all the data together and dividing the result obtained by the total number of data. Thus, the mean can be obtained as follow:

Summation of data = 17+ 11 + 21 + 24 + 22

= 95

Number of data = 5

Mean = Summation of data / Number of data

Mean = 95 / 5

Mean weight = 19 pounds

Therefore, the mean weight of the data is 19 pounds

5 0

3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> $a^7 = 128$

=> $a = \sqrt[7]{128}\\ \\\\a = 2$

For the second term:

$a^6b = -224$

$b = \frac{-224}{a^6}$

$b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5$

Therefore, a = 2, b = 3.5

5 0

3 years ago

A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan

pentagon [3]

The point-slope form of a line is:

y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line

First we need to find the slope, which is (y2-y1)/(x2-x1)

m=(4--1)/(8-2)

m=5/6 and we can use either point, I'll use (8,4)

y-4=(5/6)(x-8)

That is your equation in point-slope form.

Now the standard equation of a line is ax+by=c

y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side

y-4=(5x-40)/6 multiply both sides by 6

6y-24=5x-40 add 24 to both sides

6y=5x-16 subtract 5x from both sides

-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1

5x-6y=16

8 0

3 years ago