The coordinates of point J' is (0,-2) which represent the image of J
let J (x,y) ⇒⇒⇒⇒ J' (x',y') = (0 , -2 )
The graph was dilated according to the rule:
(x,y) ⇒⇒⇒ ( 0.5x , 0.5y)
so, for the x coordinate
∴ x' = 0.5 x ⇒⇒⇒ x = 2x' = 2*0 = 0
for the y coordinate
y' = 0.5 y ⇒⇒⇒ y = 2y' = 2 * (-2) = -4
∴ The coordinates of J is ( 0 , -4 )
∴ The correct answer is the first option
15 quarters does Ethan posess! hope this helped.
Answer:
5. A
6. B
7. A
Step-by-step explanation:
