an integrated circuit voltage of 0.9 volts decreases by 0.2 volts per second how long does it take to reach a voltage of 0.3 vol
ts
1 answer:
V(t) = 0.9 - 0.2t = 0.3, t=?
-0.2t = 0.3-0.9
0.2t = 0.6
t = 5*0.6 = 3 seconds
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2/5 in a decimal form= 0.4
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divide -204 and -17 you get 12 so x=12