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3 years ago

1) Write an equation for the line.

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

1) y = (-13/6)x + (37/3)

2) -⅔

3) negative

Step-by-step explanation:

1) slope = (1.5-8)/(5-2) = -13/6

y = (-13/6)x + c

x = 2, y = 8

8 = (-13/6)(2) + c

c = 37/3

y = (-13/6)(6) + (37/3) = -⅔

2) y = (-13/6)x + (37/3)

3) since the slope is negative, the association between the variables is negative

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Determine the principal value of the function: Arc sin(square root of 3/2)

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I have corner points of:

WARRIOR [948]

The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10

So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)

Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z

------------------

Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25

Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later

Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later

Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727

------------------

In summary, we found
A = 25
B = 21
C = 39
D = 22.2727

The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)

Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)

------------------

Final Answer: 39

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3 years ago