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3 years ago

1) Write an equation for the line.

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

1) y = (-13/6)x + (37/3)

2) -⅔

3) negative

Step-by-step explanation:

1) slope = (1.5-8)/(5-2) = -13/6

y = (-13/6)x + c

x = 2, y = 8

8 = (-13/6)(2) + c

c = 37/3

y = (-13/6)(6) + (37/3) = -⅔

2) y = (-13/6)x + (37/3)

3) since the slope is negative, the association between the variables is negative

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miss Akunina [59]

Answer:

$y=39\degree$

Step-by-step explanation:

The given triangle is a right angle triangle .

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We evaluate to obtain,

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3 years ago

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3 years ago

Length of x <br> A.6 <br> B.10<br> C.6.2<br> D.8

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3 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

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$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

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2 years ago

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