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REY [17]
3 years ago
13

For the function f(x) = x2 ­ -12, find (f o f­-1)(4) A. 0 B. 4 C. 10 D. 6

Mathematics
1 answer:
slega [8]3 years ago
5 0

We actually don't need to do any computation. By definition, the inverse function f^{-1} changes the role of input and output. So, if a function f maps x onto y, the inverse function maps y onto x.

You have to think like this: if the function makes a step further, the inverse function makes that same step back.

This means that the composition f \circ f^{-1} is always the identity function f(x) = x. In fact,

(f\circ f^{-1})(x) = f(f^{-1}(x)) = x

So, for every function, you have

(f\circ f^{-1})(4) = f(f^{-1}(4)) = 4

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I need step by step help on how to work out this percentage question ​
11Alexandr11 [23.1K]

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Step-by-step explanation:

Discount

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8 0
3 years ago
A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, th
Vikki [24]

Given, a parking lot charges $3 for first hour and $2 per hour after that.

So for t hours, the parking lot charges $3 for the first hour and after first hour there is (t-1) hours left.

So for (t-1) hours it will charge $2 per hour.

The charges for (t-1) hours = $2(t-1).

Total charges for t hours for one car = $(3+2(t-1))

Now for the second car, it will charge 75% of the first car.

So the charges for second car

=$[ (3+2(t-1))(75/100)]

=$0.75(3+2(t-1))

There are 3 cars. That parking charges for the third car is also 75% of the first car.

So for third car the parking charges are same as for the second car.

Total parking charges for 3 cars

= $(3+2(t-1))+(0.75(3+2(t-1))+(0.75(3+2(t-1))

= $(3+2(t-1))+(0.75)(2(3+2(t-1))

We have got the required answer here.

The correct option is option C.

8 0
3 years ago
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

8 0
4 years ago
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