Hi there,
Please check the attached image for answer.
<em>Hope </em><em>it </em><em>helps </em><em>.</em><em>.</em><em>.</em>
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Answer:
B. The transformation was a 180° rotation about the origin.
Step-by-step explanation:
EDGE 2020 :))
b
Take a look at everything inside the brackets sqrt(50x^2) = sqrt(5*5*x*x * 2) For ever 2 factors you can bring one out and drop the other one. That means take out 5 * x * sqrt(2). Two is what is left inside the brackets. B must = 2.
c
Do the same thing here. Write all the primes under the square root. Take out 1 for every two under the root sign. sqrt(32x) = sqrt(2*2*2*2*2*x) You can bring out two 2s. There is one left over. Leave it under the root sign. The x is a loner. It stays under the root sign. c = 2 * 2 = 4.
e
Again do the prime factor thing. sqrt(18n) = sqrt(3*3*2*n) = 3*sqrt(2*n)
e = 3
g
sqrt(72*x*x) = sqrt(3 * 3* 2 * 2 * 2 * x * x) = 3 *2 * x* sqrt(2) For every 2 prime factors you can pull out 1 of them outside the square root sign. g = 6
Comment
There are many people on the net and on Brainly that will say that you should know the perfect squares from 1 to 100 (say) so 4 9 16 25 36 49 64 81 100 are the numbers that you should memorize. When they are under the root sign, their roots can be taken out as 2 3 4 5 6 7 8 9 10. For this question I think it is better to use the pairs rule I've given you above. If someone else answers they are likely to do it the way it is written up in this paragraph. It's a free country. You are free to take the answer you like best.
photomath !!! It actually works!!! It helped me pass my classes 1
