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2 years ago

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Emma invested $750 in an account paying an interest rate of 1.9% compounded quarterly. Assuming no deposits or withdrawals are m

ade, how long would it take, to the nearest tenth of a year, for the value of the account to reach $910?

2 answers:

DedPeter [7]2 years ago

4 0

Answer: 10.2

Step-by-step explanation:

storchak [24]2 years ago

3 0

Answer:

10.2

Step-by-step explanation:

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The model of a shopping mall is made using a scale of 1: 50

jekas [21]

Answer:

20 m

Step-by-step explanation:

Given that :

Scale of 1 : 50 is used to make a model

If the model has a height of 40 cm ; the height of the house is:

Then, the actual height of the house is (40 * 50) = 2000 cm

Thus the height of the house in metre is :

100cm = 1 meter

2000 cm = 2000 / 100

2000 cm = 20 meter

Height of house in meter = 20 meter

3 0

3 years ago

Pls answer these questions correctly for brainly

FinnZ [79.3K]

40 - 3k + 10k = -10 - 8k - 10

40 + 7k = -10 - 8k - 10

40 + 7k = -8k - 20

40 + 7k - 40 = -8k - 20 - 40

7k = -8k - 60

7k + 8k = -8k - 60 + 8k

15k = -60

15k/15 = -60/15

k = -4

8 0

3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

so

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers

V = <br><br><br><br><br><br> THE PICTURE WILL BE INSERTED

ANTONII [103]

What is 'V =' referring to?

4 0

3 years ago

A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and

Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95$

$= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95$

$=P( z \leq \displaystyle\frac{x - 5}{1})=0.05$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4$

Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0

3 years ago