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3 years ago

IS THIS CORRECT?

Mathematics

2 answers:

Tems11 [23]3 years ago

8 0

Answer:
Yes
Explanation:

Slav-nsk [51]3 years ago

4 0

Answer:

yes 4fl oz bottle of orange juice that costs $12 dollars is better to buy

Step-by-step explanation:

2 bottles of orange juice=8$

if you split 8$, you get 4$ that means each bottles of orange juice is 4$

so if you get 4 bottles of orange juice it is 4$x4$= 16$ The question says that 4 bottles cost 12$ its supposed to be 16$. So the 4 fl oz bottle of orange juice that costs 12$ dollars is better to buy.

1 bottle=4$ 2x4=8$ (the first equation)

1bottle=4$ 4x4=16 (the second equation) But the question says we got the bottle of orange juice for 12$ its supposed to be 16$ that is a huge discount. so yes the answer is correct.

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The (i,j) minor of a matrix A is the matrix Aij obtained by deleting row i and column j from A.

STatiana [176]

The (i,j) minor of a matrix A is the matrix Aij obtained by deleting row i and column j from A it is true.

The (i,j) minor of a matrix A is the matrix Aij obtained by deleting row i and column j from A. A determinant of an n×n matrix can be defined as a sum of multiples of determinants of (n−1)×(n−1) sub matrices.

This is done by deleting the row and column which the elements belong and then finding the determinant by considering the remaining elements. Then find the co factor of the elements. It is done by multiplying the minor of the element with -1i+j. If Mij is the minor, then co factor, $c_{ij}$ $= -1^{i+j}$ + $m_{ij}$ .

Each element in a square matrix has its own minor. The minor is the value of the determinant of the matrix that results from crossing out the row and column of the element .

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4 0

1 year ago

When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units, the radius is...

enot [183]

Answer:

c. $\frac{1}{\pi}$

Step-by-step explanation:

We have been given that the area in square units of an expanding circle is increasing twice as fast as its radius in linear units

We will use derivatives to solve our given problem.

We know that area (A) of a circle is equal to $A=\pi r^2$ .

Let us find derivative of area function with respect to time.

$\frac{dA}{dt}=\frac{d}{dt}(\pi r^2)$

Bring out constant:

$\frac{dA}{dt}=\pi \frac{d}{dt}(r^2)$

Using power rule and chain rule, we will get:

$\frac{dA}{dt}=\pi(2r)* \frac{dr}{dt}$

$\frac{dA}{dt}=2\pi r*\frac{dr}{dt}$ Here $\frac{dr}{dt}$ represents change is radius with respect to time.

We have been given that area of an expanding circle is increasing twice as fast as its radius in linear units. We can represent this information in an equation as:

$\frac{dA}{dt}=2\frac{dr}{dt}$