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3 years ago

Find the sine of ∠A.

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

Answer: The value of sin∠A = 36.86°.

Step-by-step explanation:

Since we have given that

AB = 5 units

AC = 4 units

BC = 3 units

So, we need to find the sine ∠A.

As we know the formula for "Sine":

$\sin A=\dfrac{Opposite}{Adjacent}\\\\\sin A=\dfrac{BC}{AB}\\\\\sin A=\dfrac{3}{5}\\\\\sin A=0.6\\\\A=\sin^{-1}((0.6)\\\\A=36.86^\circ$

Hence, sin∠A = 36.86°.

drek231 [11]3 years ago

6 0

Sin A=(opposite leg)/hypotenuse= 3/5=0.6
For angle A , opposite leg is BC=3
Hypotenuse = 5

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