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2 years ago

Find the slope of the line that passes through (−1, 3) and (1, 13).

Mathematics

1 answer:

Scrat [10]2 years ago

6 0

Answer:

Step-by-step explanation:

Slope = (change in y)/ (change in x)

= (13 - 3)/(1 - (-1))

= (13 - 3)/(1 + 1)

= 10/2

= 5

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Points A and Blie in plane R. Line AB does not lie in plane R. always sometimes never

FinnZ [79.3K]

Answer:

Never

Step-by-step explanation: If two points are on the same plane but a line containing those two points is not on the same plane, the statement will never be true. Picture a cube and on one face of the cube lies two points, if there is a line containing those points, the line also has to be on the same side or face. It will always run parallel to the same side but will also always be touching that side.

4 0

2 years ago

NEED IT ASAP Find the missing side. 3 is A^2 5 is B^2 what is the missing side

nignag [31]

Answer:

5.83

Step-by-step explanation:

Use the Pythagorean theorem:

3^2+5^2 = c^2

34 = c^2

sqrt34 = c

5.83 = c

4 0

3 years ago

Read 2 more answers

A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the

Stells [14]

Answer:

$\frac{5}{3}$ in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box= $L\times B\times H$

Substitute the values then we get

Volume of box=V(x)= $(8-2x)(15-2x)x=(15x-2x^2)(8-2x)$

$V(x)=120x-30x^2-16x^2+4x^3$

$V(x)=4x^3-46x^2+120x$

Differentiate w.r.t x

$V'(x)=12x^2-92x+120$

$V'(x)=0$

$12x^2-92x+120=0$

$3x^2-23x+30=0$

$3x^2-18x-5x+30=0$

$3x(x-6)-5(x-6)=0$

$(x-6)(3x-5)=0$

$x-6=0\implies x=6$

$3x-5=0\implies x=\frac{5}{3}$

Again differentiate w.r.t x

$V''(x)=24x-92$

Substitute x=6

$V''(6)=24(6)-92=52>0$

Substitute x=5/3

$V''(5/3)=24(5/3)-92=-52$

Hence, the volume is maximum at x= $\frac{5}{3}$

Therefore, the side of the square , $x=\frac{5}{3}$ in cutout that gives the box the largest possible volume.

5 0

3 years ago

Help on the second graph

Deffense [45]

Answer:

first graph:

function.

Not one-one

onto

Second graph:

Function

one-one

not onto.

Step-by-step explanation:

We know that a graph is a function if any vertical line parallel to the y-axis should intersect the curve exactly once.

A graph is one-one if any horizontal line parallel to the x-axis or domain should intersect the curve atmost once.

and it is onto if any horizontal line parallel to the domain should intersect the curve atleast once.

Hence, from the first graph:

if we draw a vertical line parallel to the y-axis then it will intersect the graph exactly once. Hence, the graph is a function.

But it is not one-one since any horizontal line parallel to the domain will intersect the curve more than once.

But it is onto, since any horizontal line parallel to the domain will intersect the curve atleast once.

Second graph

It is a function since any vertical line parallel to the co-domain will intersect the curve exactly once.

It is not one-one since any horizontal line parallel to the x-axis does not intersect the graph atmost once.

It is not onto, since any horizontal line parallel to the domain will not intersect the curve atleast once.

7 0

3 years ago

The length of a rectangular plot exceeds its breadth by 5 meters. If the perimeter of the plot be 142 m, find the dimensions of

Alexxx [7]

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3 0

3 years ago