The missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
<h3>How to find vertically opposite angles?</h3>
We want to prove that m∠BOC = 90°.
We are given that m∠AOB is a right angle triangle. Thus;
m∠BOC must also be equal to 90°
Now, since m∠BOC and m∠AOB are right angles, then it means that we must equally say that m∠DOA and m∠BOC are vertical opposite angles and they are as such equal.
Thus, the missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
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15+c=17.50
First you subtract 15 by 15 because you switch operations from adding to subtracting then you would put C under it
Second subtract 17.50 and 15 and that is 2.50 so C= 2.50
1.31779e14 is the answer to your question
Answer:
x = 18
Step-by-step explanation:
The angle vertically opposite (5x + 2) is also (5x + 2), then
(5x + 2) and (5x - 2) are same- side interior angles and sum to 180° , that is
5x + 2 + 5x - 2 = 180
10x = 180 ( divide both sides by 10 )
x = 18